Conservation of energy is one of the most powerful principles in all of physics. When only conservative forces act, total mechanical energy — the sum of kinetic and potential energy — remains constant, allowing you to relate speeds and heights without tracking the entire trajectory.
Key Concepts
Conservative Force
A force is conservative if the work it does is independent of path and depends only on start and end points. Gravity and spring force are conservative; friction is not. Conservative forces can be associated with a potential energy.
Gravitational Potential Energy
Energy stored due to height in a gravitational field: Ug=mgh, with h measured from a chosen reference level. Only differences in U matter — the reference level is arbitrary.
Elastic Potential Energy
Energy stored in a deformed spring: Us=21kx2, where x is the displacement from the natural length. Always non-negative.
Mechanical Energy
The sum of kinetic and potential energy: Emech=K+U. For systems with only conservative forces, Emech is conserved.
Conservation of Mechanical Energy
When only conservative forces do work: Ki+Ui=Kf+Uf. As an object falls, U decreases and K increases by the same amount.
Non-conservative Forces
Friction, drag, and other dissipative forces remove mechanical energy from the system, converting it to heat: ΔEmech=Wnc, where Wnc<0 for friction.
Key Equations
Gravitational PE
Ug=mgh
Valid near Earth's surface. h is height above the chosen reference point.
Elastic (spring) PE
Us=21kx2
x is displacement from the equilibrium (natural) length; k is the spring constant.
Conservation of mechanical energy
Ki+Ui=Kf+Uf
Valid when only conservative forces do work.
With non-conservative forces
Ki+Ui+Wnc=Kf+Uf
W_nc is work done by friction, drag, etc. (typically negative, reducing total mechanical energy).
Relation between force and PE
Fx=−dxdU
Conservative force is the negative gradient of potential energy. Equilibrium where dU/dx = 0.
Worked Example
Roller Coaster Loop
Problem
A roller coaster car (mass 800 kg) starts from rest at height h=40 m. Find its speed at the bottom (take g=10 m/s²). Ignore friction.
Solution
Set reference level at the bottom (hf=0). Apply conservation of mechanical energy:
Ki+Ui=Kf+Uf
0+mgh=21mvf2+0
Solve for vf (mass cancels):
vf=2gh=2×10×40=800≈28.3 m/s
AnswerSpeed at the bottom ≈ 28.3 m/s.
Practice
Exercises
7 problems
1of 7
A 4 kg ball is held 5 m above the ground (g=10 m/s2). What is its gravitational PE relative to the ground?
J
2of 7
The same ball is released from 5 m (g=10 m/s2). What is its speed just before hitting the ground?
m/s
3of 7
A spring with k=200 N/m is compressed 0.30 m. What is its elastic PE?
J
4of 7
A 2 kg block is launched from rest by the compressed spring above (Us=9 J). What is its maximum speed?
m/s
5of 7
A 70 kg skier starts from rest at height h=30 m. What is their speed at the bottom? (g=10 m/s2, ignore friction)
m/s
6of 7
A 2 kg block slides 5 m along a flat surface with μk=0.30 (g=10 m/s2). How much mechanical energy is lost to friction?
J
7of 7
A pendulum bob (0.5 kg) swings from rest at 0.8 m above the lowest point (g=10 m/s2). What is its maximum speed at the bottom?
m/s
Key Takeaways
Potential energy is defined only for conservative forces; friction has no associated potential energy.
The choice of reference level for Ug=mgh is arbitrary — only differences in U are physically meaningful.
Conservation of energy (Ki+Ui=Kf+Uf) applies whenever only conservative forces act.
Friction converts mechanical energy to thermal energy: ΔEmech=Wfriction<0.
Equilibrium points occur where dU/dx=0; stable equilibrium is at a potential energy minimum.